Optimal. Leaf size=181 \[ \frac{a \left (a^2+28 b^2\right ) \cos (c+d x)}{6 b d}+\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}+\frac{\left (2 a^2+39 b^2\right ) \sin (c+d x) \cos (c+d x)}{24 d}-\frac{3}{8} x \left (4 a^2-b^2\right )-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{2 a b \tanh ^{-1}(\cos (c+d x))}{d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d} \]
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Rubi [A] time = 0.521179, antiderivative size = 181, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.207, Rules used = {2894, 3049, 3033, 3023, 2735, 3770} \[ \frac{a \left (a^2+28 b^2\right ) \cos (c+d x)}{6 b d}+\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}+\frac{\left (2 a^2+39 b^2\right ) \sin (c+d x) \cos (c+d x)}{24 d}-\frac{3}{8} x \left (4 a^2-b^2\right )-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{2 a b \tanh ^{-1}(\cos (c+d x))}{d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d} \]
Antiderivative was successfully verified.
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Rule 2894
Rule 3049
Rule 3033
Rule 3023
Rule 2735
Rule 3770
Rubi steps
\begin{align*} \int \cos ^2(c+d x) \cot ^2(c+d x) (a+b \sin (c+d x))^2 \, dx &=-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d}-\frac{\int \csc (c+d x) (a+b \sin (c+d x))^2 \left (-8 b^2+5 a b \sin (c+d x)+\left (a^2+12 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{4 a b}\\ &=\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d}-\frac{\int \csc (c+d x) (a+b \sin (c+d x)) \left (-24 a b^2+17 a^2 b \sin (c+d x)+a \left (2 a^2+39 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{12 a b}\\ &=\frac{\left (2 a^2+39 b^2\right ) \cos (c+d x) \sin (c+d x)}{24 d}+\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d}-\frac{\int \csc (c+d x) \left (-48 a^2 b^2+9 a b \left (4 a^2-b^2\right ) \sin (c+d x)+4 a^2 \left (a^2+28 b^2\right ) \sin ^2(c+d x)\right ) \, dx}{24 a b}\\ &=\frac{a \left (a^2+28 b^2\right ) \cos (c+d x)}{6 b d}+\frac{\left (2 a^2+39 b^2\right ) \cos (c+d x) \sin (c+d x)}{24 d}+\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d}-\frac{\int \csc (c+d x) \left (-48 a^2 b^2+9 a b \left (4 a^2-b^2\right ) \sin (c+d x)\right ) \, dx}{24 a b}\\ &=-\frac{3}{8} \left (4 a^2-b^2\right ) x+\frac{a \left (a^2+28 b^2\right ) \cos (c+d x)}{6 b d}+\frac{\left (2 a^2+39 b^2\right ) \cos (c+d x) \sin (c+d x)}{24 d}+\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d}+(2 a b) \int \csc (c+d x) \, dx\\ &=-\frac{3}{8} \left (4 a^2-b^2\right ) x-\frac{2 a b \tanh ^{-1}(\cos (c+d x))}{d}+\frac{a \left (a^2+28 b^2\right ) \cos (c+d x)}{6 b d}+\frac{\left (2 a^2+39 b^2\right ) \cos (c+d x) \sin (c+d x)}{24 d}+\frac{\left (a^2+12 b^2\right ) \cos (c+d x) (a+b \sin (c+d x))^2}{12 a b d}-\frac{\cos (c+d x) (a+b \sin (c+d x))^3}{4 b d}-\frac{\cot (c+d x) (a+b \sin (c+d x))^3}{a d}\\ \end{align*}
Mathematica [A] time = 0.706621, size = 167, normalized size = 0.92 \[ -\frac{3 a^2 (c+d x)}{2 d}-\frac{a^2 \sin (2 (c+d x))}{4 d}-\frac{a^2 \cot (c+d x)}{d}+\frac{5 a b \cos (c+d x)}{2 d}+\frac{a b \cos (3 (c+d x))}{6 d}+\frac{2 a b \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )}{d}-\frac{2 a b \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )}{d}+\frac{3 b^2 (c+d x)}{8 d}+\frac{b^2 \sin (2 (c+d x))}{4 d}+\frac{b^2 \sin (4 (c+d x))}{32 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.073, size = 191, normalized size = 1.1 \begin{align*} -{\frac{{a}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{d\sin \left ( dx+c \right ) }}-{\frac{{a}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{d}}-{\frac{3\,{a}^{2}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}-{\frac{3\,{a}^{2}x}{2}}-{\frac{3\,{a}^{2}c}{2\,d}}+{\frac{2\,ab \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{3\,d}}+2\,{\frac{ab\cos \left ( dx+c \right ) }{d}}+2\,{\frac{ab\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{d}}+{\frac{{b}^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{4\,d}}+{\frac{3\,{b}^{2}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{8\,d}}+{\frac{3\,{b}^{2}x}{8}}+{\frac{3\,{b}^{2}c}{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.51355, size = 171, normalized size = 0.94 \begin{align*} -\frac{48 \,{\left (3 \, d x + 3 \, c + \frac{3 \, \tan \left (d x + c\right )^{2} + 2}{\tan \left (d x + c\right )^{3} + \tan \left (d x + c\right )}\right )} a^{2} - 32 \,{\left (2 \, \cos \left (d x + c\right )^{3} + 6 \, \cos \left (d x + c\right ) - 3 \, \log \left (\cos \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )} a b - 3 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} b^{2}}{96 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.88502, size = 398, normalized size = 2.2 \begin{align*} -\frac{6 \, b^{2} \cos \left (d x + c\right )^{5} - 3 \,{\left (4 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{3} + 24 \, a b \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) \sin \left (d x + c\right ) - 24 \, a b \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) \sin \left (d x + c\right ) + 9 \,{\left (4 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right ) -{\left (16 \, a b \cos \left (d x + c\right )^{3} - 9 \,{\left (4 \, a^{2} - b^{2}\right )} d x + 48 \, a b \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, d \sin \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.31508, size = 370, normalized size = 2.04 \begin{align*} \frac{48 \, a b \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) + 12 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 9 \,{\left (4 \, a^{2} - b^{2}\right )}{\left (d x + c\right )} - \frac{12 \,{\left (4 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a^{2}\right )}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )} + \frac{2 \,{\left (12 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} - 15 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 96 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} + 12 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 9 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 192 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 12 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 9 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 160 \, a b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 12 \, a^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 15 \, b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 64 \, a b\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{4}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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